100 ml CH3COOK 0,5 M dengan 200 ml CH3COOH 0,5 M (Ka =1×10-5)
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Pertanyaan
100 ml CH3COOK 0,5 M dengan 200 ml CH3COOH 0,5 M (Ka =1×10-5)
1 Jawaban
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1. Jawaban Robinn
→ mol CH3COOK
= 0,5 x 100ml
= 50mmol
→ mol CH3COOH
= 0,5 x 200ml
= 100mmol
pH = pKa - log a/g
pH = -log10^-5 - log 50/100
pH = 5 - log 1/2
pH = 5 - (-0,3)
pH = 5 + 0,3
pH = 5,3