diketahui f(x) = (x²-2x+3)/(x²+x+2 ). Nilai f'(1) adalah beserta cara ya

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Diketahui :

f(x) = (x² - 2x + 3) / (x² + x + 2)

misal :
u = x² - 2x + 3 
u = (1)² - 2.(1) + 3 
u = 1 - 2 + 3
u = 2

→ u' = 2x - 2
u' = 2x - 2
u' = 2.(1) - 2
u' = 0

dan
v = x² + x + 2 
v = (1)² + (1) + 2
v = 4

→ v' = 2x + 1
v' = 2.(1) + 1
v' = 3


Maka :
f(x) = u/v

f'(1) = (u'.v - u.v') / v²

f'(1) = (0.4 - 2.3) / 4²

f'(1) = (- 6) / 16

f'(1) = - 3/8

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FZA

Langsung aja y

f(x) = (x²-2x+3) / (x²+x+2)

u = (1)² - 2(1) + 3
u = 1 - 2 + 3
u = 2

u' = 2x - 2
u' = 2(1) - 2
u' = 0

v = (1)² + (1) + 2
v = 4

v' = 2x + 1
v' = 2(1) + 1
v' = 3

f(x) = u/v

f'(x) = (u'.v - u.v') / v²
f'(x) = (0.4 - 2.3) / 4²
f'(x) = -6 / 16
f'(x) = - 3/8

Semoga berguna +_+