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Pertanyaan

sebanyak 50 ml larutan ch3cooh 0,1 m (ka = 10 pangkat -5) direaksikan dengan 50 ml larutan koh 0,1 m, ph campuran yang terjadi adalah...
a. 3
b. 6 - log 7
c. 8 + log 7
d. 9 - log 7
e. 9 + log 7

1 Jawaban

  • CH3COOH + KOH → CH3COOK + H2O

    → CH3COOH
    m = 50 x 0,1 = 5
    r = 5
    s = -

    → KOH
    m = 50 x 0,1 = 5
    r = 5
    s = -

    → CH3COOK
    m = -
    r = 5
    s = 5

    M = n / v
    M = 5 / 50 + 50
    M = 5 / 100
    M = 0,05 M

    → H2O
    m = -
    r = 5
    s = 5

    [OH-] = √Kw/Kb . [anion]garam
    [OH-] = √10^-14/10^-5 . 5 x 10^-2
    [OH-] = √10^-9 . 5 x 10^-2
    [OH-] = √10^-11 x 5
    [OH-] = √10^-10 x 0,5
    [OH-] = √0,5 x 10^-5

    pOH = -log [OH-]
    pOH = 5 - log√0,5

    pH = 14 - (5 - log√0,5)
    pH = 14 - 5 + log√0,5
    pH = 9 + log√0,5
    pH = 9 + (-0,150515)
    pH = 9 - 0,150515
    pH = 8,849485
    pH = 8 + 0,849485
    pH = 8 + log7

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