Diketahui f( 2x - 1 ) = 8x pangkat 2 + x + 5 dan g(x + 7 ) = 3x + 1 tentukan: A. F(x) dan g(x) B. (f + g) (x) C. (f x g) (-2)

Langsung aja y

A.
f(2x-1) = 8x
misal :
2x - 1 = a
x = a+1 / 2

f(a) = 8(a+1 / 2)
f(a) = 4(a+1)
f(a) = 4a + 4

f(x) = 4x + 4

g(x+7) = 3x + 1
misal :
x + 7 = a
x = a-7

g(a) = 3(a-7) + 1
g(a) = 3a - 21 + 1

g(x) = 3x - 20

B.
(f+g)(x) = f(x) + g(x)

= (4x + 4) + (3x - 20)
= 7x - 16

C.
(f×g)(-2) = f(-2) × g(-2)

= (4x + 4) × (3x - 20)
= (4.(-2) + 4) × (3.(-2) - 20)
= (-8 + 4) × (-6 - 20)
= -4 × -26
= 104

Semoga berguna +_+