Matematika

Pertanyaan


tolong jawab nomor 20 dan 22
tolong jawab nomor 20 dan 22

1 Jawaban

  • 20.) garis q (3,0) dan ( 0,-2)
    m = -2-0/0-3 = 2/3
    m(p)= -3/2
    garis p melalui (3,0), persamaan :
    y-0 = -3/2 (x-3)
    2y = -3 (x-3) (A.)
    2y = -3x + 9

    22.) mobil = x, motor = y
    3x + 5y = 17 (x4) 12x + 20y = 68
    4x + 2y = 18 (x3) 12x + 6y = 54 (di eleminasi)
    14y = 14
    y = 1 (1 motor = Rp.1000)

    4x+2y=18
    4x = 18-2
    x= 16:4 = 4 ( 1mobil = Rp.4000)

    20x + 30y = (20x4000) + (30x1000)
    =80.000 + 30.000
    = Rp.110.000 (C.)