Matematika

Pertanyaan

yang Pinter MTK bntu kak!
yang Pinter MTK bntu kak!

2 Jawaban

  • V1 = 24cm^3
    1/3 . pi . r^2 . t = 24
    1/3 . pi . (d/2)^2 . t = 24
    1/3 . pi . d^2 /4 . t = 24
    1/12 . pi . d^2 . t = 24

    V2 --> d --> 3d
    t --> 2t

    1/12 . pi . (3d)^2 . 2t = ...
    1/12 . pi . 9d^2 . 2t = ...
    18 . (1/12 . pi . d^2 . t) = ...
    18 x 24 = 432 cm^3 (c.)
  • Vkerucut 24cm
    kerucut diperbesar r=3r , t=2t

    Vbaru= 1/3 pr^t
    = 1/3 p(3r)^(2t)
    = 1/3 p(9r^) (2t)
    = 18×1/3 pr^t

    =18×24
    = 432cm^3.