jika sin x = 1/3√3, x di kuadran 2 , nilai tan x =

jika √3 sbagai pembilang dtulis (1/3)√3... jika ya
y = √3 dan r = 3
x = √(r² - y²) = √(9  - 3) = √6
kuadran II, x negatif
tanx = y/x = √3/-√6, atau
= -√3/(√2√3)
= -1/√2
= -(1/2)√2