Kimia

Pertanyaan

hitunglah pH lautan dibawah ini
hitunglah pH lautan dibawah ini

1 Jawaban

  • a.
    [H+] = √Ka . (0,01 M)
    [H+] = √1,5 x 10^-5 (1 x 10^-2)
    [H+] = √15 x 10^-6 x 1 x 10^-2
    [H+] = √15 x 10^-8
    [H+] = 10^-4√15
    [H+] = √15 x 10^-4

    pH = -log [H+]
    pH = 4 - log√15

    b.
    Br(OH)2 → Br2+ + 2OH-

    [OH-] = valensi . [Br(OH)2]
    [OH-] = 2 . 0,1
    [OH-] = 2 x 10^-1

    pOH = -log [OH-]
    pOH = 1 - log2

    pH = 14 - (1 - log2)
    pH = 14 - 1 + log2
    pH = 13 + log2

    c.
    H2SO4 → 2H+ + SO4^2-

    [H+] = valensi . [H2SO4]
    [H+] = 2 . 0,0025
    [H+] = 0,005
    [H+] = 5 x 10^-3

    pH = -log [H+]
    pH = 3 - log5

    d.
    Ca(OH)2 → Ca^2+ + 2OH-

    [OH-] = valensi . [Ca(OH)2]
    [OH-] = 2 . (0,005)
    [OH-] = 2 . 5 x 10^-3
    [OH-] = 10 x 10^-3
    [OH-] = 10^-2

    pOH = -log[OH-]
    pOH = 2 - log1
    pOH = 2

    pH = 14 - 2
    pH = 12

    e.
    [OH-] = √kb . (0,005)
    [OH-] = √1,5 x 10^-5 x 5 x 10^-3
    [OH-] = √7,5 x 10^-8
    [OH-] = 10^-4 √7,5
    [OH-] = √7,5 x 10^-4

    pOH = -log [OH-]
    pOH = 4 - log√7,5

    pH = 14 - (4 - log√7,5)
    pH = 14 - 4 + log√7,5
    pH = 10 + log√7,5