hitunglah pH lautan dibawah ini
Kimia
ryah20
Pertanyaan
hitunglah pH lautan dibawah ini
1 Jawaban
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1. Jawaban Robinn
a.
[H+] = √Ka . (0,01 M)
[H+] = √1,5 x 10^-5 (1 x 10^-2)
[H+] = √15 x 10^-6 x 1 x 10^-2
[H+] = √15 x 10^-8
[H+] = 10^-4√15
[H+] = √15 x 10^-4
pH = -log [H+]
pH = 4 - log√15
b.
Br(OH)2 → Br2+ + 2OH-
[OH-] = valensi . [Br(OH)2]
[OH-] = 2 . 0,1
[OH-] = 2 x 10^-1
pOH = -log [OH-]
pOH = 1 - log2
pH = 14 - (1 - log2)
pH = 14 - 1 + log2
pH = 13 + log2
c.
H2SO4 → 2H+ + SO4^2-
[H+] = valensi . [H2SO4]
[H+] = 2 . 0,0025
[H+] = 0,005
[H+] = 5 x 10^-3
pH = -log [H+]
pH = 3 - log5
d.
Ca(OH)2 → Ca^2+ + 2OH-
[OH-] = valensi . [Ca(OH)2]
[OH-] = 2 . (0,005)
[OH-] = 2 . 5 x 10^-3
[OH-] = 10 x 10^-3
[OH-] = 10^-2
pOH = -log[OH-]
pOH = 2 - log1
pOH = 2
pH = 14 - 2
pH = 12
e.
[OH-] = √kb . (0,005)
[OH-] = √1,5 x 10^-5 x 5 x 10^-3
[OH-] = √7,5 x 10^-8
[OH-] = 10^-4 √7,5
[OH-] = √7,5 x 10^-4
pOH = -log [OH-]
pOH = 4 - log√7,5
pH = 14 - (4 - log√7,5)
pH = 14 - 4 + log√7,5
pH = 10 + log√7,5