Jika tan x . √1-sin²x = 3/4 , maka nilai sin x adalah.

1-sin^2(x)=cos^2(x)
Tan x= sinx/ cosx
Tanx.akar(1-sin^2(x))=3/4
Sinx/cosx . Akar cos^2(x)=3/4
Sinx/cosx . Cosx=3/4
Sinx=3/4

Jd kn solusi terbaik ya :)

tanx . √1-sin^2x = 3/4
tanx . √cos^2x = 3/4
tanx . cosx = 3/4
sinx/cosx . cosx = 3/4
(sinx.cosx)/cosx = 3/4
sinx = 3/4