Jika f(x-1)=x-2 dan g(x)=2-x/x+3, maka nilai (g^-1 o f)(1) adalah A. -6 B. -2 C. -1/6 D. 1/4 E. 4

Langsung aja y

f(x-1) = x-2
f(x) = (x+1) - 2
f(x) = x + 2 - 2
f(x) = x

g(x) = 2-x / x+3
y = 2-x / x+3
y(x+3) = 2-x
xy + 3y = 2 - x
xy + x = 2 - 3y
x(y+1) = 2-3y
x = (2-3y) / (y+1)

g`¹(x) = (2 - 3x) / (x + 1)


(g`¹of)(1) = g`¹{f(1)}

= (2 - 3x) / (x + 1)
= (2 - 3) / (1 + 1)
= - ½

jawabannya gak ada

semoga berguna +_+