Matematika

Pertanyaan

tolong nomor 46 dan 47
tolong nomor 46 dan 47

1 Jawaban

  • 26.
    Panjang juring
    210/360 × 2 phi x 18
    = 7 / 12 × 36 phi
    = 21 phi

    panjang jari2 baru
    2 phi r = 21 phi
    r = 21/2 = 10,5 cm (D)

    27.
    Panjang juring
    = 3/5 × 2 × phi × 20
    = 24 phi

    panjang jari2 baru
    2 phi r = 24 phi
    r = 24/2 = 12 cm

    tinggi kerucut
    t^2 = 20^2 - 12^2 = 400 - 144 = 256
    t = 16 cm (D)