Jika f(2x + 1) = 6x + 7, maka f(10)=

f (2x + 1) = 6x + 7

f (2x + 1) = f (10)
2x + 1 = 10
2x = 10 - 1
2x = 9
x = 9/2

f (10)
= 6 (9/2) + 7
= 3 (9) + 7
= 27 + 7
= 34

f(2x + 1) = 6x + 7
f (a) = 3(2x + 1) + 4
=6x + 3 + 4
= 6x + 7
jadi rumus f (a) = 3a + 4

f (10) = 3.10 + 4
= 30 + 4
=34