persamaan garis yg melalui titik (2,-1) dan (3,5) adalah... a.y=5x-3 b.y=4x+8 c.y=6x-13 d.y=2x+1

m = (5-(-1))/(3-2) = 6/1 = 6

udah nampak jwbannya.
C. y = 6x - 13 ==> m = 6

atau
pakai rumus
y-y1 = m (x - x1)
ambil titik (3,5) => x1 = 3 ; y1 = 5

y-5 = 6(x-3)
y-5 = 6x - 18
y = 6x -18 + 5
y = 6x - 13

Bab Persamaan Garis
Matematika SMP Kelas VIII

(y - y1) / (y2 - y1) = (x - x1) / (x2 - x1)
(y + 1) / (5 + 1) = (x - 2) / (3 - 2)
y + 1 = 6x - 12
y = 6x - 12 - 1
y = 6x - 13

◎◎ C ◎◎