pada gambar berikut diketahui besar <ABD = <BCE = 130° dan <DCE = 100° hitunglah besar. a. < BAD b.<CED c.<CDE d. <BADE di kasih caranya ya.....

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1 Jawaban

  • a. <BAD = <BDA
    = 180 - 130 / 2
    = 50/2 = 25°
    b. pertama cari <CDE
    = <DBC = 50 ( 180 - 130)
    = <DCB = 30 ( 130 - 100)
    = <CDB = 180 - ( 50 + 30)
    = 180 - 80 = 100
    <CDE = 180 - (<BDA + <CDB)
    = 180- (25+100)
    = 180-125
    = 55
    <CED = 180 - ( 100 + 55)
    = 180 - 155
    = 25
    c. <CDE = 180 - (25+100)
    = 180-125 = 25
    d. <BADE = <BAD = 25

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