Diketahui 2 log 7=a dan 2 log 3=b,maka nilai dari 6 log 28 adalah..

Dik:
²log7 = a
²log3 = b

Dit:
⁶log28 = ??

Jwb:
⁶log28
= (²log28)/(²log6)
= (²log7.2²)/(²log3.2)
= (²log7 + ²log2²)/(²log3 + ²log2)
= (²log7 + 2.²log2)/(²log3 + ²log2)
= (a + 2.1)/(b + 1)
= (a + 2)/(b + 1)