jwb no 1..Tolong jwb dengan benar dan pakek caranya..!!

a) CP = AD = 8cm
b)PB = AB - CD
         = 20cm - 10cm = 10cm
c)BC = [tex] \sqrt{ 10^{2}- 8^{2}} [/tex] =6 cm
d)kel = AB + BC + CD + DA 
         = 16 + 6 + 10 + 8 = 40cm
e) luas = 1/2 x ( DC + AB) x PC
            = 1/2 x (10 + 16) x 6
            =78
f) Luas permukaan = 2x luas alas + keliling x tinggi
                               = 2 x 78 + 40 x 8
                               = 1568
g) v. prisma = L.alas x BE
                   = 78 x 20 =1560

kalau ada salah mohon dimaafka :)

diket :
AD = 8 cm
CD = 10 cm
AB = 16 cm
BE = 20 cm

jawab :
a) CP = AD
CP = 8 cm

b) PB
PB = AB - AP --> AP = CD
PB = 16 - 10
PB = 6 cm

c)BC
BC² = PB² + CP²
BC² = 6² + 8²
BC² = 36 + 64
BC² = 100
BC = akar (100)
BC = 10 cm

d) K trapesium
= AB + BC + CD + AD
= 16 + 10 + 10 + 8
= 44 cm

e) L trapesium
= ½ (a + b) t
= ½ (AB + CD) AD
= ½ (16 + 10) 8
= ½ . 26 . 8
= 104 cm²

f) L permukaan prisma
= (2 . Ltrapesium) + (BE . BC) + (BE . CD) + (BE . AD) + (BE . AB)
= ( 2 . 104 ) + (20 . 10) + (20 . 10) + (20 . 8) + (20 . 16)
= 208 + 200 + 200 + 160 + 320
= 1088 cm²

g) V prisma
Ltrapesium . t
Ltrapesium . BE
104 . 20
2080 cm³