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Pertanyaan

jika diketahui Ksp Ni(OH)2 =1x10^-14, pH larutan jenuh Ni(OH)2 adalah

1 Jawaban

  • Ni(OH)2-> Ni^2+ + 2OH-

    Ksp = [Ni^2+][OH-] ^2
    1x10^-14=(s) (2s) ^2
    1x10^-14=4s^3
    2,5 x 10^-15 = s^3
    1,35 x 10^-5 = s

    [OH-] =2s=2(1,35 x 10^-5)=2,7 x 10^-5

    pOH = -log 2,7 x 10^-5 = 5-log 2,7
    ph=14-pOH=14-(5-log 2,7)=9+log 2,7

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