Titik puncak fungsi kuadrat f(x)=2x2-4x+1 adalah

x= -b/2a = -(-4) / 2×2 = 4/4 = 1

f(1) = 2×(1)^2 - 4×1 + 1 = 2-4+1 = -1

jd titik puncaknya (1, -1)

f(x)=2x2-4x+1
a = 2 , b =-4 , c = 1
D = b^2 - 4ac
= -4^2 - 4.2.1
=16 - 8 = 8
X = -b/2a = -(-4)/2.2 = 1
Y = -d / 4a =-8 / 4.2 = 1

Jadi titik puncak (1,1)