turunan pertama f(x) = x²-4x-5/x²-1 adalah F '(X). nilai F ' (0) + F ' (3) - F(2) = ... tolong dibantu yaaa

rasanya gt cranya, maap klo slah ya

f(x) = x²-4x-5/(x²-1)

*Difaktorkan pembilangnya (yang atas)
x²-4x-5 = (x+1)(x-5)

*Difaktorkan penyebutnya (yang bawah)
x²-1 = (x-1)(x+1)

Jadi, f(x) = (x+1)(x-5)/(x-1)(x+1)
[coret (x+1) atas dan bawah]

f(x) = (x-5)/(x-1)

Turunan pecahan:
f(x) = u/v
maka
f'(x) = (u'.v - u.v')/v²

f'(x) = ((1)(x-5) - (x-1)(1))/(x-1)²
f'(x) = (x-5-x+1)/(x-1)²
f'(x) = -4/(x-1)² → didapat fungsi turunan f'(x)

f'(0) = -4/(0-1)²
f'(0) = -4/(-1)²
f'(0) = -4

f'(3) = -4/(3-1)²
f'(3) = -4/(2)²
f'(3) = -1

f(2) = (2-5)/(2-1)
f(2) = -3/1
f(2) = -3

Maka:
f'(0) + f'(3) - f(2) = -4 + (-1) - (-3)
= -2 ✔