100 ml larutan NaOh 0,2 m dicampur dg 100 ml larutan ch4cooh 0,5 m dik ka ch3cooh 1 x 10^-5 Tentujan a.pH NaOH sebelum dicampur b.ph larutan setelah dicampur

ph NaOH sebelum reaksi ;
[OH-] = 0,2 x 1 = 2 x 10^-1
pOH= 1 - log 2
pH = 14 - (1-log 2)
      = 13 + log 2
n garam = 0,2 mmol
v total = 200 ml
[G] = 0,2 mmol: 200 ml =10^-3
pH campuran
[OH-]= √kw/ka x [G]
                       = √10^-14/10^-5x10^-3
                       =√10^-12
                       =10^-6
pOH = 6
pH= 14-6
     = 8