Matematika

Pertanyaan

No 19 dan 20 gimana??? Pakai caranya ya..
No 19 dan 20 gimana??? Pakai caranya ya..

2 Jawaban

  • 20.L. lingkaran=phi×r2
    =22/7×28^2
    =2464 cm
    L. juring= =90°/360°=luas juring/2464
    =1/4=aob/2464
    4aob=2464
    Aob=2464÷4=616 CM
    L.Segitiga=1/2×a×t
    =1/2×28×28
    =1/2×784=92 CM
    L. Yg diarsir=LUAS JURING-LUAS SEGITIGA
    =616-92=524 CM
  • 19) L = L segitiga 1 + L segitiga 2
    = (1/2×12×16) + (1/2×15×20)
    = 96 + 150 = 246 m^2 (C)
    20) L = L 1/4 lingkaran - L segitiga samasisi siku-siku
    L = (1/4 × phi × r^2) - (1/2 × r^2)
    = (1/4 × 22/7 × 28^2) - (1/2 × 28^2)
    = 616 -392
    = 224 cm^2 (C)
    Gambar lampiran jawaban Sutr1sn0