Tolong ya yg nomer 13 itu pake caranya

f(x)=3x+1/x-3
f(x)=y

untuk buat jadi invers , tukar kan x menjadi y dan y menjadi x lalu cari persamaannya

x = 3y+1/y-3
xy-3x = 3y +1
xy-3y = 1+3x
(x-3)y=1+3x
y= 1+3x / x-3
f'(x) = 1+3x / x-3
f'(2) = 1+ 6 / -1
f'(2) = -7

f(x) = (3x + 1)/(x - 3) = u/v
u = 3x + 1 => u' = 3
v = x - 3 => v' = 1
f'(x) = (u' v - v' u)/v^2
f'(x) = (3(x - 3) - 1(3x + 1))/(x - 3)^2
f'(x) = (3x - 9 - 3x - 1)/(x - 3)^2
f'(x) = -10/(x - 3)^2
f'(2) = -10/(2 - 3)^2 = -10/(-1)^2 = -10/1 = -10