persamaan garis singgung parabola y2=8x yang ditarik dari titik (1,3) adalah

y² = 8x
2y dy = 8 dx
dy/dx = 8/2y = 4/y = 8/√8x
gradien (m) = dy/dx (x = 1) = 8/√8(1) = 8/√8 = 8/2√2 = 4/√2 = 2√2
persamaan garis singgungnya :

y - b = m(x - a)
y - 3 = 2√2 (x - 1)
y = 2√2(x - 1) + 3

y² = 8x
puncak ( 0, 0)
p = 2
y - 0 = m ( x - 0 ) + [tex] \frac{2}{m} [/tex]
y = mx + [tex] \frac{2}{m} [/tex] melalui titik ( 1, 3 )
3 = m + [tex] \frac{2}{m} [/tex]
3m = m² + 2
m² - 3m + 2 = 0
( m - 2 ) ( m - 1 ) = 0
m - 2 = 0
m = 2
atau
m - 1 = 0
m = 1
persamaan garis singgung:
1. y = 2x + [tex] \frac{2}{2} [/tex]
y = 2x + 1
2. y = 1x + [tex] \frac{2}{1} [/tex]
y = x + 2