Matematika

Pertanyaan

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1 Jawaban

  • Persamaan kurva...
    .
    d²y/dx² = y" = 3 - 4x  melalui (1,4) ejajar  2x + y + 7= 0
    gradien gs 2x+y+ 7 = 0 ---> m = -2

    m= y' = ∫ y" dx = ∫ 3-4x dx
    m = 3x - 2x² + c
    melalui (x,y)= 1,4 --> x = 1
    m = 3(1) - 2(1)² + c = -2
    3 - 2 + c = -2
    1 + c= -2
    c = -3
    y' = 3x - 2x²  - 3

    y =∫ y' dx = ∫ 3x - 2x² - 3
    y= 3/2 x² - 2/3 x³ - 3x + c melalui (x,y) = (1,4)
    4 = 3/2 (1)² - 2/3(1)³ - 3(1) + c
    4 = 3/2 - 2/3 +3 +  c ...kalikan 6
    24 = 9 - 4  +18 +  6c
    24 = 23 + 6c
    c = 1/6
    persamaan  y = -2/3 x³ + 3/2 x² - 3x + 1/6
    atau  y = 1/6 ( -4x³ + 9x² - 18 x + 1)